为什么uint8_t类型变量无利用c++进行打印-创新互联

本篇文章为大家展示了为什么uint8_t 类型变量无利用c++进行打印，内容简明扼要并且容易理解，绝对能使你眼前一亮，通过这篇文章的详细介绍希望你能有所收获。

将uint8_t 转化为unsigned 类型

使用一元运算符+(和- 运算符对应)

测试代码如下

#include 
#include 
#include 
int main()
{
 std::uint8_t uint8_num = 10;
 std::cout << "uint8_t num is " << uint8_num << std::endl; //无法打印
 std::cout << "after cast to unsigned, uint8_t num is " << unsigned(uint8_num) << std::endl; //能正常打印
 std::cout << "with a unary + operator, uint8_t num is " << +uint8_num << std::endl; //能正常打印
 std::cout << "type of '+uint8_num' is " << typeid(+uint8_num).name() << std::endl;
 return 0;
}